Number and Algebra Sec 2 E-Mathematics

Algebraic Expressions and Formulae

Algebraic Expressions and Formulae

Key Concepts

  • Algebra uses letters and numbers to represent values and relationships.

    • Letters such as xx, yy, and aa are called variables.
    • A variable can stand for an unknown value or a value that can change.
  • An algebraic expression is a mathematical phrase made up of numbers, variables, and operations such as ++, -, ×\times, and ÷\div.

    • Examples: 3x+53x+5, 2a27a2a^2-7a, x+13\frac{x+1}{3}
  • A term is one part of an expression, separated by ++ or -.

    • In 4x23x+64x^2-3x+6, the terms are 4x24x^2, 3x-3x, and 66.
  • A coefficient is the numerical part of a term.

    • In 7y7y, the coefficient is 77.
    • In 2a2-2a^2, the coefficient is 2-2.
  • A constant is a fixed number without a variable.

    • In x2+4x9x^2+4x-9, 9-9 is the constant.
  • Like terms are terms with the same variable part.

    • 3x3x and 5x-5x are like terms.
    • 2a22a^2 and 7a27a^2 are like terms.
    • 4x4x and 4x24x^2 are not like terms.

1. Expansion of Products of Algebraic Expressions

  • Expansion means removing brackets by multiplying each term inside the bracket.

  • Use the distributive law:

    a(b+c)=ab+ac a(b+c)=ab+ac

Expanding a single bracket

  • Multiply the term outside the bracket by every term inside.

  • Example:

    3(x+4)=3x+12 3(x+4)=3x+12

Expanding two brackets

  • Multiply every term in the first bracket by every term in the second bracket.

  • Example:

    (x+2)(x+5)=x2+5x+2x+10=x2+7x+10 (x+2)(x+5)=x^2+5x+2x+10=x^2+7x+10
  • After expanding, always collect like terms.


2. Standard Algebraic Identities

An identity is an equation that is true for all values of the variables.

You must know these standard identities:

Square of a sum

(a+b)2=a2+2ab+b2 (a+b)^2=a^2+2ab+b^2

Square of a difference

(ab)2=a22ab+b2 (a-b)^2=a^2-2ab+b^2

Product of a sum and a difference

(a+b)(ab)=a2b2 (a+b)(a-b)=a^2-b^2

Important notes

  • (a+b)2(a+b)^2 does not mean a2+b2a^2+b^2
  • The middle term comes from multiplying the two terms twice:
    • ab+ab=2abab+ab=2ab

3. Factorisation of Algebraic Expressions

  • Factorisation is the reverse of expansion.
  • It means writing an expression as a product of factors.

Common factor

  • Find the highest common factor of all the terms and take it out.

  • Example:

    6x+9=3(2x+3) 6x+9=3(2x+3)

Factorising by grouping

  • Sometimes terms can be grouped to form common factors.

  • Example:

    ax+ay+bx+by=a(x+y)+b(x+y)=(a+b)(x+y) ax+ay+bx+by=a(x+y)+b(x+y)=(a+b)(x+y)

Using identities

  • Recognise patterns:
    • a2+2ab+b2=(a+b)2a^2+2ab+b^2=(a+b)^2
    • a22ab+b2=(ab)2a^2-2ab+b^2=(a-b)^2
    • a2b2=(a+b)(ab)a^2-b^2=(a+b)(a-b)

4. Factorising Quadratic Expressions ax2+bx+cax^2+bx+c

  • A quadratic expression has highest power 22.

  • General form:

    ax2+bx+c ax^2+bx+c

    where a0a\neq 0

When a=1a=1

  • Factorise x2+bx+cx^2+bx+c by finding two numbers:
    • whose product is cc
    • whose sum is bb

Example:

x2+7x+12=(x+3)(x+4) x^2+7x+12=(x+3)(x+4)

because 3×4=123\times4=12 and 3+4=73+4=7

When a1a\neq1

  • Find two numbers:
    • whose product is acac
    • whose sum is bb
  • Then split the middle term and factorise by grouping.

Example:

2x2+7x+3 2x^2+7x+3
  • a×c=2×3=6a\times c=2\times3=6
  • Need two numbers that multiply to 66 and add to 77: 66 and 11

So,

2x2+7x+3=2x2+6x+x+3 2x^2+7x+3=2x^2+6x+x+3
=2x(x+3)+1(x+3) =2x(x+3)+1(x+3)
=(2x+1)(x+3) =(2x+1)(x+3)

5. Changing the Subject of a Formula

  • A formula is an equation that shows a relationship between quantities.

    • Example:

      A=12bh A=\frac{1}{2}bh
  • The subject of a formula is the variable that is written alone on one side.

    • In A=12bhA=\frac{1}{2}bh, the subject is AA
  • Changing the subject means rearranging the formula so that a different variable is the subject.

Steps

  1. Identify the variable to make the subject.
  2. Remove addition or subtraction first.
  3. Remove multiplication or division next.
  4. Keep the equation balanced by doing the same operation to both sides.

Example:

A=12bh A=\frac{1}{2}bh

Make hh the subject.

  • Multiply both sides by 22:

    2A=bh 2A=bh
  • Divide both sides by bb:

    h=2Ab h=\frac{2A}{b}

6. Operations with Algebraic Fractions

An algebraic fraction is a fraction that contains variables.

Example:

2x+1x3 \frac{2x+1}{x-3}

Simplifying algebraic fractions

  • Factorise the numerator and denominator first.
  • Cancel only common factors, not terms.

Example:

x29x3=(x3)(x+3)x3=x+3 \frac{x^2-9}{x-3}=\frac{(x-3)(x+3)}{x-3}=x+3

Multiplication

  • Multiply numerators together and denominators together.
  • Factorise first if possible.

Example:

x3×6x+1=6x3(x+1)=2xx+1 \frac{x}{3}\times\frac{6}{x+1}=\frac{6x}{3(x+1)}=\frac{2x}{x+1}

Division

  • Change division into multiplication by the reciprocal.
  • Reciprocal means flipping the fraction.

Example:

x4÷2x+3=x4×x+32=x(x+3)8 \frac{x}{4}\div\frac{2}{x+3} = \frac{x}{4}\times\frac{x+3}{2} = \frac{x(x+3)}{8}

Addition and subtraction

  • Find a common denominator first.
  • Then combine the numerators.

Example:

x2+32=x+32 \frac{x}{2}+\frac{3}{2}=\frac{x+3}{2}

Example with different denominators:

1x+23x \frac{1}{x}+\frac{2}{3x}

Common denominator is 3x3x:

1x=33x \frac{1}{x}=\frac{3}{3x}

So,

1x+23x=33x+23x=53x \frac{1}{x}+\frac{2}{3x}=\frac{3}{3x}+\frac{2}{3x}=\frac{5}{3x}

Restriction

  • The denominator of a fraction cannot be zero.
  • If x3x-3 is in the denominator, then x3x\neq3

Important Definitions

  • Variable: a letter that represents an unknown value or a value that can change.
  • Algebraic expression: a combination of numbers, variables, and operations.
  • Term: a part of an algebraic expression separated by ++ or -.
  • Coefficient: the numerical factor of a term.
  • Constant: a number without a variable.
  • Like terms: terms with the same variable part.
  • Expansion: removing brackets by multiplication.
  • Distributive law: the rule a(b+c)=ab+aca(b+c)=ab+ac.
  • Identity: an equation that is true for all values of the variables.
  • Factorisation: writing an expression as a product of factors.
  • Common factor: a factor shared by two or more terms.
  • Quadratic expression: an expression with highest power 22, usually written as ax2+bx+cax^2+bx+c.
  • Formula: an equation showing the relationship between quantities.
  • Subject of a formula: the variable that is alone on one side of the equation.
  • Algebraic fraction: a fraction involving variables.
  • Reciprocal: the multiplicative inverse of a number or fraction; for ab\frac{a}{b}, the reciprocal is ba\frac{b}{a}.

Worked Examples

Example 1: Expand and simplify (2x+3)(x4)(2x+3)(x-4)

Step 1: Multiply each term in the first bracket by each term in the second bracket

(2x+3)(x4) (2x+3)(x-4)
=2x(x)+2x(4)+3(x)+3(4) =2x(x)+2x(-4)+3(x)+3(-4)

Step 2: Simplify each product

=2x28x+3x12 =2x^2-8x+3x-12

Step 3: Collect like terms

=2x25x12 =2x^2-5x-12

Answer:

(2x+3)(x4)=2x25x12 (2x+3)(x-4)=2x^2-5x-12

Example 2: Change the subject of v=u+atv=u+at to tt

We want tt to be the subject.

Step 1: Remove uu from the right side

v=u+at v=u+at

Subtract uu from both sides:

vu=at v-u=at

Step 2: Remove aa

Divide both sides by aa:

t=vua t=\frac{v-u}{a}

Answer:

t=vua t=\frac{v-u}{a}

Example 3: Factorise 2x2+5x32x^2+5x-3

Step 1: Identify aa, bb, and cc

a=2,b=5,c=3 a=2,\quad b=5,\quad c=-3

Step 2: Find acac

ac=2(3)=6 ac=2(-3)=-6

Step 3: Find two numbers with product 6-6 and sum 55

These are 66 and 1-1

Step 4: Split the middle term

2x2+5x3=2x2+6xx3 2x^2+5x-3=2x^2+6x-x-3

Step 5: Factorise by grouping

=2x(x+3)1(x+3) =2x(x+3)-1(x+3)

Step 6: Take out common bracket

=(2x1)(x+3) =(2x-1)(x+3)

Answer:

2x2+5x3=(2x1)(x+3) 2x^2+5x-3=(2x-1)(x+3)

Common Mistakes to Avoid

  • Expanding (a+b)2(a+b)^2 as a2+b2a^2+b^2

    • Correct form is a2+2ab+b2a^2+2ab+b^2
  • Forgetting to multiply every term in a bracket.

    • In (x+2)(x+3)(x+2)(x+3), you must get 4 products.
  • Sign errors when multiplying negatives.

    • Example: (3)(+2)=6(-3)(+2)=-6, (3)(2)=+6(-3)(-2)=+6
  • Collecting unlike terms.

    • 3x+2x23x+2x^2 cannot be simplified further.
  • Cancelling terms instead of factors in algebraic fractions.

    • x+3x\frac{x+3}{x} cannot be simplified by cancelling the xx
  • Forgetting to factorise before simplifying fractions.

    • Example: x24x2\frac{x^2-4}{x-2} must first become (x2)(x+2)x2\frac{(x-2)(x+2)}{x-2}
  • Rearranging a formula incorrectly by moving terms without using inverse operations.

    • Always do the same operation to both sides.
  • Leaving the final answer unsimplified.

    • Always collect like terms or cancel common factors where possible.
  • Forgetting restrictions for algebraic fractions.

    • If the denominator is x5x-5, then x5x\neq5

Exam Tips

  • When expanding brackets, write out all products clearly before simplifying.
  • Use identities only when the expression matches the pattern exactly.
  • In factorisation, always check your answer by expanding the factors again.
  • For x2+bx+cx^2+bx+c, look for two numbers with:
    • product = constant term
    • sum = coefficient of xx
  • For ax2+bx+cax^2+bx+c, first calculate acac.
  • When changing the subject of a formula:
    • state or show each operation on both sides
    • keep the target variable positive if possible
  • In algebraic fractions:
    • factorise first
    • state common denominator when adding or subtracting
    • cancel only common factors
  • Watch signs carefully, especially when the constant term is negative.
  • If your factorised answer has brackets, make sure each bracket is as simple as possible.

Quick Summary

  • An algebraic expression contains variables, numbers, and operations.
  • Expansion means removing brackets by multiplication.
  • Use the distributive law: a(b+c)=ab+aca(b+c)=ab+ac
  • (a+b)2=a2+2ab+b2(a+b)^2=a^2+2ab+b^2
  • (ab)2=a22ab+b2(a-b)^2=a^2-2ab+b^2
  • (a+b)(ab)=a2b2(a+b)(a-b)=a^2-b^2
  • Factorisation is the reverse of expansion.
  • To factorise, first look for a common factor.
  • For x2+bx+cx^2+bx+c, find two numbers whose product is cc and sum is bb.
  • For ax2+bx+cax^2+bx+c, find two numbers whose product is acac and sum is bb, then group.
  • To change the subject of a formula, use inverse operations on both sides.
  • For algebraic fractions, factorise first and cancel only common factors, not terms.
✏️ 26 practice questions available

30 questions from school exam papers

Q1

The table of values below is for the straight line y = -3 - 2x.

Diagram for question 5
Math_Sec2NA_SA2_2023_ACS_Barker 2023
Q2

The diagram shows part of a regular 18-sided polygon, ABCDE .... Calculate (a) angle ABC,

Diagram for question 6
2 marks
Math_Sec2NA_SA2_2023_ACS_Barker 2023
Q3

Simplify: (4x²)/(5y) ÷ (15xy²)/(2z)

2 marks
Math_Sec2NA_SA2_2023_ACS_Barker 2023
Q4

Simplify: (4a² - b²)/(6a - 3b)

2 marks
Math_Sec2NA_SA2_2023_ACS_Barker 2023
Q5

Simplify (2p - 3)/(q - 4)² ÷ (8p² - 12p)/(q - 4)³, giving your answer as a single fraction.

3 marks
Math_Sec2NA_SA2_2023_ACS_Barker 2023
Q6

Find the value of p.

Diagram for question 5a
1 mark
Math_Sec2NA_SA2_2023_ACS_Barker 2023
Q7

Find an expression for m in terms of r.

2 marks
Math_Sec2NA_SA2_2023_Bartley_Sec 2023
Q8

Expand and simplify (4y − 3)(2y + 5).

2 marks
Math_Sec2NA_SA2_2023_Bartley_Sec 2023
Q9

Factorise completely: 4mn + 2n

1 mark
Math_Sec2NA_SA2_2023_Bartley_Sec 2023
Q10

Factorise completely: x² + 6x + 9

1 mark
Math_Sec2NA_SA2_2023_Bartley_Sec 2023
Q11

Factorise completely: 9x² - 4

2 marks
Math_Sec2NA_SA2_2023_Bartley_Sec 2023
Q12

Find an expression for m in terms of r.

2 marks
Math_Sec2NA_SA2_2023_Bartley_Sec 2023
Q13

Expand and simplify (2x+5)² - 3(4x-1).

3 marks
Math_Sec2NA_SA2_2023_Bartley_Sec 2023
Q14

Hence prove that (2x+5)² - 3(4x-1) is an even number for all integer values of x.

2 marks
Math_Sec2NA_SA2_2023_Bartley_Sec 2023
Q15

Factorise 4x³ - 4x - 3.

Diagram for question 9(a)
1 mark
Math_Sec2NA_SA2_2023_Bartley_Sec 2023
Q16

Hence simplify (4x - 2)/(4x³ + 4x - 3).

Diagram for question 9(b)
2 marks
Math_Sec2NA_SA2_2023_Bartley_Sec 2023
Q17

Expand and simplify the following: 3a(9a+1) + 2(10 - 2a²)

2 marks
Math_Sec2NA_SA2_2023_Bedok_View_Sec 2023
Q18

Expand and simplify the following: (6c + 7)²

2 marks
Math_Sec2NA_SA2_2023_Bedok_View_Sec 2023
Q19

Factorise the following completely: 3b² - 8b + 4

2 marks
Math_Sec2NA_SA2_2023_Bedok_View_Sec 2023
Q20

16d³ - 8d² - 12d

1 mark
Math_Sec2NA_SA2_2023_Bedok_View_Sec 2023
Q21

A rectangle has a length of x cm and a breadth which is 1/3 of the length. Given that the perimeter of the rectangle is 48 cm, write down an expression, in terms of x, to represent the perimeter of the rectangle.

Diagram for question 4a(i)
1 mark
Math_Sec2NA_SA2_2023_Bedok_View_Sec 2023
Q22

Given that (a + b)² = 64 and ab = 15, find the value of a² + b².

Diagram for question 4
2 marks
Math_Sec2NA_SA2_2023_Bedok_View_Sec 2023
Q23

Simplify the following. (3xz + 3yz)/(x² + xy)

Diagram for question 7(a)
2 marks
Math_Sec2NA_SA2_2023_Bedok_View_Sec 2023
Q24

Simplify the following. (5x - 15y)/(6x - 8y) + (4x - 12y)/(9x - 12y)

Diagram for question 7(b)
3 marks
Math_Sec2NA_SA2_2023_Bedok_View_Sec 2023
Q25

A bookshop sells pens at $x each and notebooks at $y for a pack of 6. Ali bought 9 pens and 3 packs of notebooks. He paid $36. Show that 3x + y = 12

1 mark
Math_Sec2NA_SA2_2023_Broadrick_Sec 2023
Q26

Sarah bought 16 pens and 8 packs of notebooks. She paid $76. Show that 4x + 2y = 19

1 mark
Math_Sec2NA_SA2_2023_Broadrick_Sec 2023

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